y^2+8=4y-12

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Solution for y^2+8=4y-12 equation:


Simplifying
y2 + 8 = 4y + -12

Reorder the terms:
8 + y2 = 4y + -12

Reorder the terms:
8 + y2 = -12 + 4y

Solving
8 + y2 = -12 + 4y

Solving for variable 'y'.

Reorder the terms:
8 + 12 + -4y + y2 = -12 + 4y + 12 + -4y

Combine like terms: 8 + 12 = 20
20 + -4y + y2 = -12 + 4y + 12 + -4y

Reorder the terms:
20 + -4y + y2 = -12 + 12 + 4y + -4y

Combine like terms: -12 + 12 = 0
20 + -4y + y2 = 0 + 4y + -4y
20 + -4y + y2 = 4y + -4y

Combine like terms: 4y + -4y = 0
20 + -4y + y2 = 0

Begin completing the square.

Move the constant term to the right:

Add '-20' to each side of the equation.
20 + -4y + -20 + y2 = 0 + -20

Reorder the terms:
20 + -20 + -4y + y2 = 0 + -20

Combine like terms: 20 + -20 = 0
0 + -4y + y2 = 0 + -20
-4y + y2 = 0 + -20

Combine like terms: 0 + -20 = -20
-4y + y2 = -20

The y term is -4y.  Take half its coefficient (-2).
Square it (4) and add it to both sides.

Add '4' to each side of the equation.
-4y + 4 + y2 = -20 + 4

Reorder the terms:
4 + -4y + y2 = -20 + 4

Combine like terms: -20 + 4 = -16
4 + -4y + y2 = -16

Factor a perfect square on the left side:
(y + -2)(y + -2) = -16

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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